I would still submit that if a card printer can make a mistake on one rule (failing to put a 3 on the other side of a D) then he can also make a mistake printing a letter on the back of a letter. And you can only be sure that he didn't make that mistake by turning over the K to make sure there isn't a D on the other side.QillerDaemon wrote: ↑Fri Aug 18, 2023 6:28 pm"A card manufacturer makes a set of cards that have a letter on one side of a card and a number on the other side."Animal wrote: ↑Fri Aug 18, 2023 5:30 pm I am going to have to argue this point. Let's just simply talk about one card. The "K" card. In your explanation, you say that you don't have to turn it over to figure out if the rule has been broken. But let's say there is a "D" on the other side of the card.
That's a given from the original problem. All cards have one letter on one side and one number on the other side.
No card is going to have two letters or two numbers on both sides of each card.
Interesting Math Problems
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Re: Interesting Math Problems
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Re: Interesting Math Problems
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Re: Interesting Math Problems
I'm up early.
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Re: Interesting Math Problems
if 25% is the right answer and there are two choices that are 25%, then wouldn't there be a 50% random chance of choosing the right one?
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Re: Interesting Math Problems
I agree, the correct answer can be chance B alone, or chances A and C together. Or both answers.
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Re: Interesting Math Problems
Three circles of equal circumference sit co-linear and tangent. A line is drawn from the center of the first circle, through the second circle, and tangent to the third circle. What is the length of the chord made by the line going through the second circle? If it helps, assume the circumference of each circle is 10π.
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“All mushrooms are edible. Some even more than once!”
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Re: Interesting Math Problems
A right triangle ABC is drawn with perimeter = 336 units and area = 3360 units2. Sides c > b > a. What are the lengths of the sides of the triangle?
(hint: set up a system of three equations and substitute between them)
(hint: set up a system of three equations and substitute between them)
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Re: Interesting Math Problems
a=48QillerDaemon wrote: ↑Thu Mar 07, 2024 3:44 pm A right triangle ABC is drawn with perimeter = 336 units and area = 3360 units2. Sides c > b > a. What are the lengths of the sides of the triangle?
(hint: set up a system of three equations and substitute between them)
b=140
c=148
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Re: Interesting Math Problems
Solve: 6 + f(x) = 2f(-x) + 3x2*INT(from -1 to +1)f(t)dt
To clarify, "3x2*INT(from -1 to +1)f(t)dt" means 3x2 times the integral from -1 to 1 of f(t)dt.
Cuz I don't know how to make the cute skinny integral "S" sign.
Exam question from a recent Oxford math entrance test. 96% of the test takers could not solve it.
To clarify, "3x2*INT(from -1 to +1)f(t)dt" means 3x2 times the integral from -1 to 1 of f(t)dt.
Cuz I don't know how to make the cute skinny integral "S" sign.
Exam question from a recent Oxford math entrance test. 96% of the test takers could not solve it.
If you can't be a good example, you can still serve as a horrible warning.
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“All mushrooms are edible. Some even more than once!”
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Re: Interesting Math Problems
Animal says hold my Pabst ....QillerDaemon wrote: ↑Tue Jul 09, 2024 1:36 am Solve: 6 + f(x) = 2f(-x) + 3x2*INT(from -1 to +1)f(t)dt
To clarify, "3x2*INT(from -1 to +1)f(t)dt" means 3x2 times the integral from -1 to 1 of f(t)dt.
Cuz I don't know how to make the cute skinny integral "S" sign.
Exam question from a recent Oxford math entrance test. 96% of the test takers could not solve it.
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Re: Interesting Math Problems
Well, the integral of f(t)dt from 1 to -1 would be t^2/2 + t^2/2 which would be = 1. So, all of that equals 1.
You are then left with 6+y = -2y +3x^2
Which reduces to y = x^2 - 2 or f(x) = x^2 - 2
You are then left with 6+y = -2y +3x^2
Which reduces to y = x^2 - 2 or f(x) = x^2 - 2
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Re: Interesting Math Problems
"When governments fear the people, there is liberty. When the people fear the government, there is tyranny."
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Re: Interesting Math Problems
A rectangle of unknown dimensions is drawn, then inside the rectangle is drawn a circle of unknown radius that does not touch the rectangle.
From each internal corner of the rectangle is drawn a line segment which touches a point tangent to the circle. The lengths of three of these line segments is known, but not the fourth; the known segments are 10 units, 34 units and 85 units (for the sake of this problem). Calculate the length of the unknown line segment.
edit - I realize now that the problem's description is quite vague in one detail: the line segment from the corner could go tangent on one side of the circle or the other. Unless the segments are consistent on how they extend to the circle, the problem has no real solution, or a solution dependent on how the circles become tangent. So the line segments are tangent in a circular way in a right-hand direction, this is so the segments can't ever actual cross each other.
From each internal corner of the rectangle is drawn a line segment which touches a point tangent to the circle. The lengths of three of these line segments is known, but not the fourth; the known segments are 10 units, 34 units and 85 units (for the sake of this problem). Calculate the length of the unknown line segment.
edit - I realize now that the problem's description is quite vague in one detail: the line segment from the corner could go tangent on one side of the circle or the other. Unless the segments are consistent on how they extend to the circle, the problem has no real solution, or a solution dependent on how the circles become tangent. So the line segments are tangent in a circular way in a right-hand direction, this is so the segments can't ever actual cross each other.
If you can't be a good example, you can still serve as a horrible warning.
“All mushrooms are edible. Some even more than once!”
これを グーグル 翻訳に登録してくれておめでとう、バカ。
“All mushrooms are edible. Some even more than once!”
これを グーグル 翻訳に登録してくれておめでとう、バカ。
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Re: Interesting Math Problems
I don't have the time at the moment to attempt it, but i would start with this.
For each corner (say A, B, C, D) you have created a right triangle like this:
Let's say A has the 10 unit length that is tangental to the circle. We know a tangental segment hits a circle at 90 degrees to the radius. So we have a right Triangle A that has one side of 10 and one side of r. So the remaining side is the distance from the centerpoint of the circle to the corner A. That distance is A^2 = 10^2 + r^2. Now, you know that same information for two of the other corners. With r^2 being the common distance in each. And that would give you a way to find the two sides of the rectangle. Working backward with the same thing you could find the length of D.
That would take some time, though.
For each corner (say A, B, C, D) you have created a right triangle like this:
Let's say A has the 10 unit length that is tangental to the circle. We know a tangental segment hits a circle at 90 degrees to the radius. So we have a right Triangle A that has one side of 10 and one side of r. So the remaining side is the distance from the centerpoint of the circle to the corner A. That distance is A^2 = 10^2 + r^2. Now, you know that same information for two of the other corners. With r^2 being the common distance in each. And that would give you a way to find the two sides of the rectangle. Working backward with the same thing you could find the length of D.
That would take some time, though.